Question

For the circuit shown in figure calculate the charge on 4μF capacitor–

Answer 1

Answer:

24μC

So total charge flow =q=5.4μF×10V

=54μC

The charge will be distributed in the ratio of capacitance

⇒

q

2

q

1

=

3

2.4

=

5

4

∴9X=54μC⇒X=6μC

∴ Charge on 4μF capacitor

will be =4X=4×6μC

=24μC