Question

For the circuit shown in the diagram below: What is the value of: (i) current through 6 ohm resistor? (ii) p.d. across 12 ohm​

Answer 1

AnswEr :

According to the diagram, Potential difference is 4 V.

Now, let's calculate the total resistance in both the lines and then we'll calculate Current and Potential difference.

• Total resistance in 1st line = R1 = 6 + 3 = 9 ohm

• Total resistance is 2nd line = R2 = 12 + 3 = 15 ohm

1] Current through 6 ohm resistor :

$\star \: \: { \underline{ \sf{Current \: in \: 1st \: line :}}} \\ \\ :\implies \sf \: \dfrac{V}{R1} \\ \\ :\implies \sf \: \dfrac{4}{9} \\ \\ :\implies \sf \: \blue{0.44 \: A}$

2] Potential difference across the resistor :

$\star \: \: { \underline{ \sf{Current \: in \: 2nd \: line:}}} \\ \\ :\implies \sf \: \dfrac{V}{R2} \\ \\ :\implies \sf \: \green{\frac{4}{15} \: A }$

Now,

Let's calculate Potential difference across 12 ohm resistor.

$: \implies \sf \: \: PD = Current \: in \: 2nd \: line \times 12 \\ \\ \\ : \implies \sf \: \:PD = \dfrac{4}{15} \times 12 \\ \\ \\ : \implies \sf \: \:{ \underline{ \boxed{ \bf{ \purple{PD = 3.2 V}}}}} \: \: \bigstar$

Therefore, Potential difference across 12 ohm resistor is 3.2 V and current through 6 ohm resistor is 0.44 A.