.for the circuit shown in the diagram given below 1.calculate
a.the total effective resistance of the circuit
b.the total current drawn from the battery
c.the value of current through each resistor
2.draw a circuit diagram to show an electric lamp of resistance 30 ohm and a series of 6 ohm connected in series with a battery of 6v
calculate:a)total resistance in circuit
b)current flowing through the circuit
c)potiential difference separetely across the lamp and the resistor
3.draw a schematic diagram of an electric circuit consisting of a battery of six 2v cells (12v)a 10 ohm resistor a20 ohm resistor as plug key all connected in series .calculate the value of current flowing through the 10 ohm resistor and the power consumed by the 20 ohm resistor.
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1. where is the circuit????
2. a) resistance in series(1/Rs)=1/R1+1/R2
1/Rs=1/30+1/6 =6/30
Rs=30/6 ohm
b) current flowing I=?
I=V / R = 6 / 6 X 30= 30 A
c) V1=IR1 =>V1=30 X 30 =900v
V2=IR2=>V2=30 X 6 =180v
3.see the pic
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2. a) resistance in series(1/Rs)=1/R1+1/R2
1/Rs=1/30+1/6 =6/30
Rs=30/6 ohm
b) current flowing I=?
I=V / R = 6 / 6 X 30= 30 A
c) V1=IR1 =>V1=30 X 30 =900v
V2=IR2=>V2=30 X 6 =180v
3.see the pic
MARK ME AS BRAINLIEST
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