Physics, asked by sonisharma6177, 1 year ago

for the circuit shown in the figure the resultant resistance second the total current third the voltage across 7 ohm resistor

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Answered by brainlyaryan12

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Total resistance of the circuit-

$\frac{1}{R_p}$ = $\frac{1}{5}+\frac{1}{10}$

=> $\frac{1}{R_p}$ = $\frac{1+2}{10}$

=> $\frac{1}{R_p}$ = $\frac{3}{10}$

=> $R_p$ = $\frac{10}{3}$ ohm

$R_s$ = 7+ $\frac{10}{3}$

=> $R_s$ = $\frac{31}{3}$ ohm

Current through whole circuit =

I = $\frac{V}{R}$

I = $\frac{6}{\frac{31}{3}}$

I = $\frac{18}{31}$

=> $\huge\orange{\fbox{\pink{ I=0.58A}}}$

$\huge{\purple{\bigstar{\blue{\text{Hope it helps...}}}}}$

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