for the coagulation of 100 ml of arsenic sulphide solution, 5 ml of 1M NaCl is required. What is the coagulation power of Nacl
Answers
Answered by
3
Answer:
Total volume after addition of 5mL of 1M NaCl solution =105mL
Thus, 105× molarity of NaCl in colloidal solution = 5×1
Molarity of NaCl in colloidal solution =
105
5
Concentration in millimole =
105
5
×100=47.6
please mark this as brainliest :) ^^
Answered by
4
Answer:
5mL of 1MNaCl contains NaCl=11000×5mol=5mmol
Thus, 100mL of As2S3sol require NaCl for complete, coagulation =5mmol
∴ 1L, i.e., 1000mL of the sol requires NaCl for complete, coagulation =50mmol
Therefore, the flocculation value of NaCl=50
Explanation:
Similar questions