Question

For the compound C-H-C-CH = CH-CH3


i) Write its complete structure.


ii) Identify the number of sigma and pi bonds.


iii) Identify the type of hybridisation of each carbon atom.


iv) Write the bond line formula of the compound.


v) Mention whether the compound in saturated or unsaturated.

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Answer 1

Answer:

v) saturated

iv) n C176H250, X = 176, Y = 250, therefore P = (2 x 176 – 250)/2 +1 = 51 + 1 = 52 number of π bonds or double bonds. where, X = number of carbon atoms; Y = number of hydrogen atoms and S = number of sigma bonds (σ-bonds).

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Answer 2

Answer:

    H H H    H  H

      |   |   |      |   |

i) H-C-C-C = C-C-H      ii) 14 sigma 1 pi bonds     iii) C1 sp3, C2 sp3, C3 sp2

      |   |              |                                                         C4 sp2 , C5 sp3

     H  H           H

iv) CH3C2CHCHCH3

v) Unsaturated                                                      

Explanation:

i) complete structure is as follows

  H H H    H  H

      |   |   |      |   |

 H-C-C-C = C-C-H      

      |   |              |                                                      

     H  H           H

ii) The number of sigma and pi bonds are

      sigma = 14

       pi = 1

iii) The type of hybridisation of each carbon atom is

C1 sp3, C2 sp3, C3 sp2 , C4 sp2 , C5 sp3

iv) The bond line formula of the compound is

  CH3C2CHCHCH3

v)the compound in saturated or unsaturated

  It is unsaturated as it has a pie bond.