Chemistry, asked by ataullasharifataulla, 5 months ago

for the cu atom calculate
by zeff for 3d electron
zeff for 4s electron
zeff for periphery
of
cu atom​

Answers

Answered by shruthi4841
3

Answer:

what is this anyway be happy

Answered by meuginedhanraj
0

Answer:

2.2

Explanation:

Effective nuclear charge Z

eff

=Z−S

where Z = atomic number

and S = screening constant

      = 0.35 per electron for electron in nth orbit.

      = 0.85 per electron for electrons in (n - 1)th orbit

      = 1.00 per electron for electrons in (n - 2)th, (n - 3)th, (n - 4)th orbit

      = 0.30 per electron in 1s-orbital (when alone)

This electron is screened by 18 electrons in (n - 1), 8-electrons in (n - 2) and 2-electrons in (n-3)

Thus, σ=

8×0.85

​(n−1)s 2p6 + 1×10(n−1)d 10+ 8×1(n−2)s 2p6 + 2×1(n−3)s 2

=26.8

Thus, Z

=29−26.8=2.2

Similar questions