For the cubic polynomial P (x)= x3-10x2+31x-30 the sum of the product of the zero taken two a time (-31,30,31)
Answers
Answered by
0
Step-by-step explanation:
Let the roots of given equation x
3
+kx
2
+31x−30=0 is p,q,r
by given condition,
p×q=15
Relation betwen roots and coefficients are
Product of the roots=
a
−d
∴p×q×r=
a
−d
=
1
−(−30)
=30
15r=30
r=2,
Sum of products of the roots taken two at a time=
a
c
∴p×q+p×r+q×r=
a
c
=
1
31
=31
15+r(p+q)=31
r(p+q)=16
p+q=16/2=8 and also
pq=15
So p+q+r=
a
−b
=
1
−k
=−k
(p+q)+r=−k
8+2=−k
k=−10
Similar questions