Math, asked by avanisumathy, 1 year ago

For the curve y = (2x + 1)^3 find the rate of change of slope at x = 1

Answers

Answered by sureshbhat47
0
slope = dy/dx = 3 ( 2x + 1 )2

rate  of  change  of  slope = 6( 2x + 1 ) = 6* 3 = 18  at  x = 1

Answer = 18


Answered by aburaihana123
1

The rate of change of slope at x = 1 for the curve is 54

Step-by-step explanation:

Given: y = (2x+1)^{2} is the given equation

To find : The rate of change of slope at x = 1

Formula used : (\frac{d}{dx} )(x^{n} ) =  nx^{n-1}

solution,

The equation of the curve

y = (2x+1)^{2}

Differentiate the above equation with respect to x

The we get,

y^{'}  = 3(2x +1)^{2} .2

y^{'}  = 6(2x +1)^{2}

Rate of change of slop at x = 1

Now sub the value of x = 1  in the above equation

y^{'}  = 6(2x +1)^{2}

y^{'}  = 6(2(1) +1)^{2}

y^{'}  = 6(2 +1)^{2}

y^{'}  = 6(3)^{2}

y^{'}  = 6(9)

y^{'}  = 54

Final answer:

The rate of change of slope for the curve is 54.

#SPJ2

Similar questions