Question

For the decomposition of the compound represented as nh2coonh4 gives 2nh3+co2 the kp=2.9*10^-5

Answer 1

Answer:

NH  

2

​

COONH  

4

​

(s)⇌2NH  

3

​

(g)+CO  

2

​

(g)K  

P

​

=2.9×10  

−5

atm  

3

 

at                            1                             0                   0

t=0

at                       1−x                         2P                  P

t=t  

eq

​

 

Let total pressure at equilibrium be P

Partial pressure of CO  

2

​

=2P

Partial pressure of NH  

3

​

==P

K  

P

​

=(2P)  

2

(P)=2.9×10  

−5

atm  

3

 

P=1.93×10  

−2

 

3P=5.82×10  

−2

Explanation: