Question

for the decomposition reaction for hn O3 in equilibrium with 4 and O2 + 2 H2O + O2 if we start with only the reactant hn O3 and P is equal to equilibrium pressure the equilibrium constant KP is​

Answer 1

Explanation:

4HNO3=4NO2+2H2O+O2

let partial pressure be p

Ptotal=P(HNO3)+P(H2O)+P(O2)

Initially for HNO3 pressure =p

and NO2,H2O,O2= 0

at equilibrium: for HNO3 pressue=P- (PHNO3+PH2O+PO2)

4HNO3= 4NO2+2H2O+O2

Initially:P    0        0        0

equilibrium:p-(phno3+ph2o+po2)=phno3  ph2o   po2

(in terms of po2), PNO2=4PO2

PH2O=2PO2

KP=P[NO2]4 P[H2O]2 P[O2] / P[HNO3]

KP=[4PO24][2PO2]2[O2] / [P-7PO2]4

KP=1024[PO2]7 / [P-7PO2]4

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