Question

for the displacement time graph as shown ,the ratio of magnitude of velocity during the first two sec.
and next four sec. is

Answer 1

From graph :

Displacement in first 2s , D =20 m

so, velocity = D/t =20/2 =10 m/s

Displacement in next 4 s i.e., 2s to 6s

= 20-0 m = 20 m

So, velocity= 20/4 = 5 m/s

Hence, required ratio = 10/5 =2 : 1.

Answer 2

Answer:

V1 : V2 = -2 : 1

Step-by-step explanation:

Given that,

for the displacement time graph as shown .

To find the ratio of magnitude of velocity during the first two sec and next four sec.

Now,

Displacement = ( final position - initial position )

Velocity =  $\frac{ Displacement }{Time}$

1) Velocity of body during first 2 seconds.

The displacement of body in 2 sec = ( final position - initial position )

                                                          = ( 20 - 0 ) units

                                                          = 20 units

And the time taken = 2 seconds.

Velocity(V1) = $\frac{20}{2}$

             = 10 units/s

2) Velocity of body next four seconds.

The displacement of body in next 4 sec = ( final position - initial position )

                                                          = ( 0 - 20) units

                                                          = -20 units

And the time taken = 4 seconds.

Velocity(V2)= $\frac{-20}{4}$

             = -5 units/s

The ratio of their magnitude -

V1/V2 = 10/-5

         = -2/1

V1 : V2 = -2 : 1

THANKS.

#SPJ3.

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