Question

For the electrode Pt, H2 (g, 1 atm) | H+ (aq) (x M), the reduction electrode potential at 25°C is – 0.34V. Write the electrode reaction and calculate the value of x. and the pH of solution.​

Answer 1

Nernst Equation

The cell Pt, H2 (1 atm) | H...

The cell Pt, H2(1atm)∣H+(pH=x)∣∣ Normal calomel Electrode has an EMF of 0.67 V at 25∘C. The pH of the solution is:

The oxidation potential of the calomel electrode on hydrogen scale is −0.28V. (write the value to the nearest integer)

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ANSWER

Ecell=Ecalomel−Ehydrogen

0.67V=0.28−Ehydrogen

Ehydrogen=−0.39V

Ehydrogen=Ehydrogen0−n0.0592log[H+]2PH2

−0.39=0−20.0592log