Question

For the equation 3x² + px + 3 = 0, if one root is square of the other root, then p =?
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Answer 1

Answer:

$p = - 6 \\ let \: \alpha = \alpha \\ \beta = { \alpha }^{2} \\ \alpha + \beta = - p \div 3 \\ 1 + \alpha = - p \div 3 \alpha \\ \alpha \beta = 3 \div 3 = 1 \\ \alpha \times { \alpha }^{2} = 1 \\ { \alpha }^{3} = 1 \\ \alpha = 1 \\ x1 + 1 = - p \div 3 \\ p = - 6$