For the equation f(x)=-2x^2 +x+6 : determine the values of k such that f(x)=k has equal roots
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Answer:
2x2 + 4x - 3x + 6= 2x( x+2) - 3(x+2)= (2x -3) (x+2)
so (2x-3)= 0 or (x+2)= 0
so real roots are 3/2 and -2
PLS MARK BRAINLIEST
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