Question

for the equation find alpha +beta and alpha beta a²-3a+2=0​

Answer 1

$\huge\tt\colorbox{orange}{Answer}$

a² - 3a + 2

a = 1 , b = -3 , c = 2

$sum \: of \: the \: roots = \alpha + \beta = \frac{ - b}{a} \\ \\ \alpha + \beta = \frac{ - ( - 3)}{1} \\ \\ \alpha + \beta = \frac{3}{1} \\ \\ \alpha + \beta = 3$

$product \: of \: roots = \alpha \times \beta = \frac{c}{a} \\ \\ \alpha \times \beta = \frac{2}{1} \\ \\ \alpha \times \beta = 2$

Answer 2

$\huge\tt\colorbox{pink}{Answer}$

GɪᴠᴇN:

• a² - 3a + 2=0

• a = 1 , b = -3 , c = 2

SᴏʟᴜᴛɪᴏN:

$\begin{gathered}sum \: of \: the \: roots = \alpha + \beta = \frac{ - b}{a} \\ \\ \alpha + \beta = \frac{ - ( - 3)}{1} \\ \\ \alpha + \beta = \frac{3}{1} \\ \\ \alpha + \beta = 3\end{gathered}$

$\begin{gathered}product \: of \: roots = \alpha \times \beta = \frac{c}{a} \\ \\ \alpha \times \beta = \frac{2}{1} \\ \\ \alpha \times \beta = 2\end{gathered}$