Question

for the equilibrium. SO2cl2 ≈ So2 + Cl2 what is the temperature. at which Kp/Kc. = 3

Answer 1

hope u understand if not please reply

Answer 2

Answer: 36.54K

Explanation:

$\frac{K_p}{K_c}=(RT)^\Delta n_g)$

where $K_p$= equilibrium constant in terms of pressure

$K_c$= equilibrium constant in terms of concentration

$\Delta n_g$ = number of moles of gaseous products- number of moles of gaseous reactants

R = Gas constant = 0.0821 Latm/Kmol

T= temperature in Kelvin

$SO_2Cl_2(g)\rightleft harpoons SO_2(g)+Cl_2(g)$

Thus $\Delta n_g=(2-1)=1$

tex]3=(0.0821\times T)^1[/tex]

$T=36.54K$