Question

For the experiment of tossing a six sided die twice, what is the probability that the sum is 2, 3 or 12?

Answer 1

Sample space

(1, 1),(1, 2),(1, 3),(1, 4),(1, 5),(1, 6)

(2, 1),(2, 2),(2, 3),(2,4), (2, 5),(2, 6)

(3, 1),(3, 2),(3, 3),(3,4), (3, 5),(3, 6)

(4, 1),(2, 2),(2, 3),(2,4), (2, 5),(4, 6)

(5, 1),(5, 2),(5, 3),(5,4), (5, 5),(5, 6)

(6, 1),(6, 2),(6, 3),(6,4), (6, 5),(6, 6)

Total outcomes = 36 (for 2 die)

P(sum is 2)= 2/36 = 1/18

P(sum is 3)= 3/36 = 1/12

P(sum is 12)= 12/36 = 1/3