For the first 2 km,the fare is Rs.6 and for the successive distance the fair is Rs.2 per km.Taking total distance as x kmand total fare as Rs y, write a linear equation in x and y.
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since the fare of 1st 2km is 6rs and the fare of next (x-2)kms is 2rs.....and the total fare of x kms is y rs .......
sothe equation is ....
6 + (x-2)*2= y
=>6+2x-4 = y
=>2x-y+2 =0
sothe equation is ....
6 + (x-2)*2= y
=>6+2x-4 = y
=>2x-y+2 =0
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