Question

for the following circuit V source =15v,R1,=25Ω ,and v2=5.6v. what is the

Answer 1

Answer:

Let current in R  

1

​

 be I  

1

​

 and R  

2

​

 be I  

2

​

 and R  

3

​

 be I  

3

​

 respectively away from the junction.

Let junction potential be V

By Kirchhoff junction law,

10

V−10

​

+  

20

V−6

​

+  

30

V−5

​

=0

60

11V

​

=  

6

7

​

+  

10

3

​

=  

60

88

​

 

V=  

11

88

​

 

V  

1

​

=(10−  

11

88

​

)=2

I  

1

​

=  

R  

1

​

 

V  

1

​

 

​

=  

10

2

​

=0.2 Amp

Explanation: