Question

For the following distribution:
Class: 0-8 8-16 16-24 24-32 32-40
Freq. : 12 26 10 9 15
The sum of upper limit of the median class and modal class is:

Answer 1

The sum of upper limit of the median class and modal class is as follows

Median class is 8 - 16

Modal class is also 8 - 16

then the required answer is 16+16=> 32...

Answer 2

The Sum of upper limit of median class and modal class=32

Step-by-step explanation:

Modal class: That class whose frequency is highest.

By definition of modal class

Modal class=8-16

Upper limit of modal class=16

Class:0-8   8-16   16-24 24-32 32-40

Freq  : 12      26       10       9       15

C.f:       12       38       48     57     72

Sum of frequencies=$12+26+10+9+15=72$

n=72 =Even

Median class=$\frac{(\frac{72}{2})^{th}+(\frac{72}{2}+1)^{th}}{2}=\frac{36th+37th}{2}=\frac{38+38}{2}=38$

It lies in interval 8-16

Median class=8-16

Upper limit of median class=16

Sum of upper limit of median class and modal class=16+16=32

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