For the following equations, calculate the mass of the second reactant needed to completely react with 100.0 g of the first reactant (mass -mass problems).
4NH3 + 5O2 → 4NO + 6H2O
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4NH3 needs 5O2
10NH3 needs 12.5O2
therefore mass of O2 is 12.5 × 32
10NH3 needs 12.5O2
therefore mass of O2 is 12.5 × 32
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