Question

For the following G.P.s find tn

1)√3, 1/√3, 1/3√3, 1/9√3 ,...​

Answer 1

$\star\;{\underline{\boxed{\pmb{\green{\frak{\;Given\; :-}}}}}}$

• $\tt\:\sqrt 3 \:, \dfrac{1} {√3},\:\dfrac{1}{3√3},\:\dfrac{1}{9√3}$

$\star\;{\underline{\boxed{\pmb{\green{\frak{\;To\:Find\; :-}}}}}}$

• $\large\underline\color{red}{\sf{an}}$

$\star\;{\underline{\boxed{\pmb{\green{\frak{\; Solution\; :-}}}}}}$

Here first term ==> $\sqrt 3$

$\huge\rightarrow$ Common term = $\dfrac{1}{3}$

$\huge\rightarrow$ So, $a_{1}$ $\sqrt 3 =$ $\dfrac{1}{3}$

$\huge\rightarrow$ So nth term a$r ^{n-1}$

So , therefore

$\Huge\sf\implies$ $\star\;{\underline{\boxed{\pmb{\pink{\frak{\;an\:=\:(\sqrt3)\: sqrt\dfrac{1}{3})}}}}}}$