For the following hypothetical chemical equilibrium Aaq) 2B(aq) + C(aq). It was
found that initially only A and B are present with mole fraction of B equal to 1/3. At
equilibrium mole fraction of A becomes equal to 1/2. So K, for the above equilibrium is.
Initial molarity of the 'B' is 'M'.
1) (3/4)M
2) (9/28)M^2
3) (7/28)M
4) (1/7)M
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Explanation:
initial moles of B and A must be in terms of M
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