for the following molecule and ion ALCL3 and NH2,
1. draw the shape showing the ions pair [s] and bond pair [s] of electrons.
2.state bond angle [s]
3.give the overall polarity
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We have : Aluminium Chloride (AlCl3) and Amide ion (NH2) (-).
1) Aluminum Chloride :
Molecular geometry : Trigonal Planar.
Structure : Three Bonds each Al-Cl.
No lone pairs on Al. (central atom)
Amide ion : (NH2 )(-1)
Molecular Geometry : Bent / Angular.
2)
In AlCl3,
Bond Angle between each bonds is 120° .
In Amide, (NH2) (-))
Bond angle between two bond pairs is 104.5°.
3) Polarity will be such that partial negative charge is more stable on more electrinegative atom and vice -versa.
=>Cl has partial negative charge as its mire electronegative than Al.
=>H has partial positive charge as its more electropositive.
1) Aluminum Chloride :
Molecular geometry : Trigonal Planar.
Structure : Three Bonds each Al-Cl.
No lone pairs on Al. (central atom)
Amide ion : (NH2 )(-1)
Molecular Geometry : Bent / Angular.
2)
In AlCl3,
Bond Angle between each bonds is 120° .
In Amide, (NH2) (-))
Bond angle between two bond pairs is 104.5°.
3) Polarity will be such that partial negative charge is more stable on more electrinegative atom and vice -versa.
=>Cl has partial negative charge as its mire electronegative than Al.
=>H has partial positive charge as its more electropositive.
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Given molecule Here :- AlCl₃ & (NH₂)⁻
Now We have to find the shape,bond angle and polarity . Thus
The structure of AlCl₃ is Trigonal Planer & Hybridisation is SP₂.
The structure of NH₂⁻ is Bent , Also It has two Bond pair & two lone pair.
⇒(i) Refer to the attachment for the diagrammatic structure for showing the lone pair & Bond pair of the electron.
(a) AlCl₃ . :- It doesn't have lone pair of electron & it is stable.
(b) NH₃⁻ :- It has two lone pair & also unstable.
⇒(ii) For Bond Angle :-
(a) AlCl₃ (Aluminium Trichloride) :- As we know , the structure of AlCl₃ is Trigonal Planer, The Bond angle bonded with 3 Chlorine atoms is 120°. Each chlorine atoms are sharing 1 pair of electron with Al for completing the valence shell.
(b) NH₂⁻ :- As the structure of NH₂⁻ is bent , Then the bond angle between two atoms is 104.5° .
⇒ (iii) Overall Polarity :-
(a) AlCl₃ :- We know the electronegativity of Aluminium is 1.61 and that of Chlorine is 3.16 . Thus electronegativity difference is 1.55 , This means that the shared pair of electron are tilted towards the chlorine atoms(Hence it Polar Compound). Thus a Dipole is created here . in which chlorine has the negative charge and Al has the positive .
(b) NH₂⁻ -: The NH₂⁻ is a polar compound because it Tends to attract the electron towards itself . This creates a negative charge on the compound.
Hope it Helps..
Now We have to find the shape,bond angle and polarity . Thus
The structure of AlCl₃ is Trigonal Planer & Hybridisation is SP₂.
The structure of NH₂⁻ is Bent , Also It has two Bond pair & two lone pair.
⇒(i) Refer to the attachment for the diagrammatic structure for showing the lone pair & Bond pair of the electron.
(a) AlCl₃ . :- It doesn't have lone pair of electron & it is stable.
(b) NH₃⁻ :- It has two lone pair & also unstable.
⇒(ii) For Bond Angle :-
(a) AlCl₃ (Aluminium Trichloride) :- As we know , the structure of AlCl₃ is Trigonal Planer, The Bond angle bonded with 3 Chlorine atoms is 120°. Each chlorine atoms are sharing 1 pair of electron with Al for completing the valence shell.
(b) NH₂⁻ :- As the structure of NH₂⁻ is bent , Then the bond angle between two atoms is 104.5° .
⇒ (iii) Overall Polarity :-
(a) AlCl₃ :- We know the electronegativity of Aluminium is 1.61 and that of Chlorine is 3.16 . Thus electronegativity difference is 1.55 , This means that the shared pair of electron are tilted towards the chlorine atoms(Hence it Polar Compound). Thus a Dipole is created here . in which chlorine has the negative charge and Al has the positive .
(b) NH₂⁻ -: The NH₂⁻ is a polar compound because it Tends to attract the electron towards itself . This creates a negative charge on the compound.
Hope it Helps..
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