Question

For the following pair of liner equations,
2/x + 2/Зу = 1/6
3/x + 2/y = 0
the value of 'a' for which y = ax + 4 is ​

Answer 1

Answer:

Step-by-step explanation:

x2​+3y2​=61​;x3​+y2​=0

Let x1​=u and y1​=v

2u+32​v=61​

12u+4v=1...(I)

3u+2v=0...(II)

Multiply (II) with 2

6u+4v=0...(III)

(I) - (III)

12u−6u+4v−4v=1−0

6u=1

⇒u=61​

Putting the value of u in II

3×61​+2v=0

⇒21​+2v=0

⇒v=4−1​

x1​=u

⇒x=6

y1​=v

⇒y=−4

(x,y) = (6, -4)