Question

For the formation of 3.65 g of hcl gas,what volume of h2 and cl2 gas required at ntp

Answer 1

The equation for formation of HCl is :

H₂(g) + Cl₂(g) — > 2HCl (g)

The mole ratio of Hydrogen to Chlorine to Hydrogen Chloride is :

1 : 1 : 2

The moles of HCl formed is :

Molar mass of HCl = 35.5 + 1 = 36.5g/mol

Moles = mass /molar mass

3.65 / 36.5 = 0.1 moles

Moles of Hydrogen and Chlorine gas is :

0.1/2 = 0.05 moles

Molar gas volume at NTP is :

22.4 litres

22.4 × 1000 = 22400 Cm³

0.05 × 22400 = 1120cm³

The hydrogen and Chlorine gas have the same volume and the volume is 1120cm³.