For the formation of 3.65g of HCl gas what volume of hydrogen gas and chlorine gas are required at NTP condition?
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H2 + Cl2 → 2 HCl1 V 1 V 2 V Now 71g HCl is obtained from = 22.4 L of Cl2 1g HCl is obtained from =22.4/71 3.65g HCl is obtained from = 22.4 × 3.65 /71 = 1.15 L of Cl2 Hence 1.15 L of Cl2 and H2 are used for formation of HCl
Sharu26:
Ans is 1.12 &1.12
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