Question

For the formation of 3.65g of HCLgas,what volumes of hydrogen gas and chlorine gas was required at NTP condition

Answer 1

H2 + Cl2 =  2 HCl
 
V      1 V         2 V

 71g HCl is obtained from = 22.4 l of cl2

 1g HCl is obtained from =22.4/71

 3.65g HCl is obtained from =  22.4 × 3.65 /71

 =  1.15 L of CL2 


Hope this helps!

Answer 2

the answer is 1.15 l of cl2 gaa