Question

for the formation of 3.75g of hcl gas what volume of hydrogen and chlorine gas are required at ntp conditions
Answer only if you know please

Answer 1

Explanation:

See you know the reaction.

H2+Cl2---->2HCl

By the equation we get to know that equal volume of H and Cl are required..

Now we know that the molar volume for a gas is same for both STP and NTP. i.e., 22.4 litres.

Therefore now by Gay Lussacs law,

1. 1 mole of Cl2---- requires 2 moles of HCl
2. i.e, 22.4 litre of Cl2---- requires 2*36.5 g of HCl(molecular mass of HCl)
3. therefore 1g of HCl----- requires 22.4/(2*36.5) litre of chlorine.
4. Therefore 3.75 g of HCl----- requires (22.4/(2*36.5))*3.75 litres of chlorine.
5. This is your ans. you can further calculate this. And the same volume will be for Hydrogen also.

Here the only technical point was that you were confused as it was given NTP instead of STP in that only temperature and pressure is more at NTP which will do the reaction faster according to the Le Chatliers principle.

Hope you understood the ans