for the function f , given by f(x)= 2x^2-3x+7 show that f'(2)=5f'(1)
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Step-by-step explanation:
F(-1)=2(-1)^2+3(-1)-5
=2(1)-3-5
=2-8
=-6
f(0)'+3f'(-1)=0
0-3f'=0
f'=0/-3
f'=0
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