Physics, asked by vedanshijhanwar, 9 months ago

For the function f(x) = cos(3x)
Find f"(π/3)

Answers

Answered by Anonymous
9

f (x)=cos (3x)

f (pi/3)=cos (3×pi/3)

f'(pi/3)=-sin(pi)

f''(pi/3)=-cos (pi)

=-1×-1

=1

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Answered by azizalasha
10

Answer:

0

Explanation:

f(x) = cos(3x)

f'(x) = -3sin(3x)

f''(x) = -9cos(3x)

f''(π/2) = -9cos(3π/2) = -9 x 0 = 0

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