Question

For the function x2 +
1, XE[1,2], the value of
c for the mean value
theorem is
5/4
7/4
03/2
2/3
​

Answer 1

Answer:

f(1,2) = f(a,b)

f(x) = [a,b]

f'(c) = f(b) - f(a) / b-a

f'(x) = 1-1

f'(c) = 1c-1

f'(c) = f(1)-f(1)/1-1

f(2) = 2×1-1×2+1 = 1

f(1) = 1×1-1×1+1 = 1

1c-1 = 1+1

1c-1 = 2

1c = 2+1

1c = 3

c = 3/1........ans.

Step-by-step explanation:

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