Question

for the funsion f(x)=sinx/x2 how many points exist in the interval [0,7π] such that f'(c)=0​

Answer 1

Answer:

We have the sine function that takes the value of zero at

Integral multiples, But for sin(x)⁄x we have the exceptional value of limx→0 sin(x)⁄x reaching one.

So leaving the first interval [0, π], for every other interval of the form [nπ (n + 1)π ] we must have f(nπ) = f((n + 1)π)

By Rolles theorem we have

f’ (c) = 0 For every interval of the form [nπ (n + 1)π ] There are 17 such intervals.

Thanks

Step-by-step explanation:

Answer 2

Answer:

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