Question

for the G.P. if r=1/3, a=9 find t7​

Answer 1

Answer:

1/81

Step-by-step explanation:

tn = ar^(n-1)

t7 = 9×(1/3)^(7-1)

t7 = 9×(1/3)⁶ = 9×1/729 = 1/81

t7 = 1/81

Answer 2

Given,

In a GP, a = 9 and $r=\frac{1}{3}$

To find,

The value of 7th term , $t_{7}$.

Solution,

In a GP, consecutive terms have a common ratio through out the sequence.

Now , we have a formula for nth term in GP, that is

$a_{n} = ar^{n-1}$

Here a is the first term.

r is the common ratio.

n is the nth term.

So we need 7 th term.

$t_{7} = a_{7} = 9(\frac{1}{3} )^{7-1}$

=$9(\frac{1}{3} )^{6}$

= $\frac{1}{81}$

Hence , the 7 th term of the GP is $t_{7} = \frac{1}{81}$ .