For the gas phase reaction,
C2H4 + H2 <=> C2H6
carried out in a vessel, the equilibrium concentration of C2H4 can be increased by??
Answers
Answered by
40
Hey there!!!
C2H4 + H2 <=> C2H6
(Delta H = -32.7kcal)
The above reaction is exothermic, increasing temperature will favour backward reaction, will increase the amount of C2H4.
Decreasing pressure will favour reaction in direction containing more molecules (reactant side in this case).
Therefore, decreasing pressure will increase amount of C2H4.
Removing H2 , which is a reactant, will favour reaction in backward direction, more C2H4 will be formed.
Hope it helps!!
# RUHANIKA
C2H4 + H2 <=> C2H6
(Delta H = -32.7kcal)
The above reaction is exothermic, increasing temperature will favour backward reaction, will increase the amount of C2H4.
Decreasing pressure will favour reaction in direction containing more molecules (reactant side in this case).
Therefore, decreasing pressure will increase amount of C2H4.
Removing H2 , which is a reactant, will favour reaction in backward direction, more C2H4 will be formed.
Hope it helps!!
# RUHANIKA
kabir414:
thank u
Answered by
14
here c2h4 and c2h6 both are in gases form and reactant are in 2 mole and product have 1 mole so if apply pressure it could go in forward direction and product is in saturate form and reactant is in unsaturated form so it process is exothermic and so the lower temperature is profit for it but lower temperature it make lower
speed so we have to use pt/pd like catalyst for fast reaction and we have to reach at optimum state
speed so we have to use pt/pd like catalyst for fast reaction and we have to reach at optimum state
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