Physics, asked by arya9178, 11 months ago

For the given block, which of its surface will exert
minimum pressure? If its weight is 6 N, calculate the
pressure in such a case.
I = 8 cm
h = 6 cm
w = 6 cm​

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Answers

Answered by wajahatkincsem
40

Answer:

The answer is 1250 N/m^2

Explanation:

As we know that the expression for pressure is

Pressure = Force / Area

Thus, we can say that maximum the area minimum will be the pressure exerted by the table. So in order to find the minimum pressure calculate the maximum area by using different combination as follows

A1 = Width x length = 6cm x 8 cm = 48cm^2

A2 = Width x height = 6cm x 6 cm = 36 cm^2

A3 = length x height =  6cm x 8 cm = 48cm^2

As A1 and A3 are same so the both will exert same pressure.

A2 = 0.06m X 0.08m = 0.0048m^2

Now calculate the pressure

Pressure = Force / Area = 6 N /  0.0048m^2

Pressure = 1250 N/m^2

Answered by alkarup
3

Answer:

1250 N/m 2

Explanation:

The block should be placed in such a way that the side with the minimum surface area is in contact with the surface

Area= L*W

=8/100m * 6/100m

=48/10000 m 2= 0.0048 m 2

weight of the block F=6N

Pressure= Force/area

6/0.0048

=1250 N/m2

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