For the given elements and their atomic numbers, which of these have the highest second ionization enthalpy?
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The atomic numbers of V,Cr,Mn and Fe are respectively 23,24,25 and 26. Which one of these may be expected to have the highest second ionization enthalpy ?
(a)V(b)Cr(c)Mn(d)Fe
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The electronic configurations are as follows;
V:(Ar)3d34s2
Cr:(Ar)3d54s1
Mn:(Ar)3d54s2
Fe:(Ar)3d64s2
The second ionization of Cr means removal of electron from the stable configuration of 3d5.
The highest second ionization enthalpy is Cr
Hence b is the correct answer.
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