Question

for the given equation C5H12+8O2->5CO2+6H2O: if the reactant C5H12 and O2 are having 2 moles and 8 moles initially a) Which is Excess reactant? b) which is limiting reagent? c) How many grams of water is formed at the end of the reaction

Answer 1

HEY MATE HERE IS YOUR ANSWER

In equation C5 at 12 + 8 O2 minus 5 SEO 2 + 6 H2O reaction was 512 and O2 having two moles and eight moles in this excess reactant Bose 802

Answer 2

The answers are as follows:

a) C₅H₁₂ is the reagent in excess.

• The excessive reagent is the one that remains even after the completion of the reaction. Here, 1 mole C₅H₁₂ reacts with 8 moles O₂, hence 2 moles C₅H₁₂ will require 16 moles O₂.

b) Oxygen is the limiting reagent.

• Since there are only 8 moles O₂, it is the limiting reagent and C₅H₁₂ is in excess.

c) 6 moles of water are formed at the end.

• The reaction proceeds according to the limiting reagent.
• 8 O₂ can produce 6 H₂O.