Question

for the given figure ratio of pressure at A and B will be if rho is 1000 and Patm =10^5​

Answer 1

Answer:

answer is 1)1/2

Explanation:

pa= ρgh₁

pB=ρgh₂

h1=10

h2=20

$\frac{10}{20}$=1/2

Answer 2

Given,

A figure of a setup where ρ is 1000 Kg/m^3 and P(atm) =10^5 pa

To find,

The ratio of pressure at points A and B.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

According to the hydrostatic pressure equation;

The pressure exerted by a column of liquid of height h and density ρ is given by the expression:

Pressure p = ρgh

(g = acceleration due to gravity)

Now, according to the question;

For point A:

The height of the column of water at point A = 10 m

So, the pressure exerted by the column of the liquid at point A

= ρgh = ρ × g × (10 m)

= 10ρg pa

=> the pressure exerted by the column of the liquid at point A = (10ρg) pa

{Equation-1}

And, for the point B;

The height of the column of water at point B = 10 m + 20 m = 30 m

So, the pressure exerted by the column of the liquid at point B

= ρgh = ρ × g × (30 m)

= 30ρg pa

=> the pressure exerted by the column of the liquid at point B = (30ρg) pa

{Equation-2}

Now, the ratio of pressure at points A and B

= (the pressure exerted by the column of the liquid at point A)/(the pressure exerted by the column of the liquid at point B)

= (10ρg) pa/(30ρg) pa

{according to equation-1 and equation-2}

= 1/3 = 1:3

Hence, the ratio of pressure at points A and B is equal to 1:3.