Math, asked by dora285, 9 months ago

For the given network, find

the current through 4 ohm and 3 ohm. Assume that the cells have negligible internal resistance.​

Answers

Answered by Anonymous
47

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Solution:

Applying Kirchhoff first lawAt junction F,

I I I 1 3 = 2 – 1 2 . 3 --- (1)

Applying Kirchhoff second law,

(i) loop EFCDE,

3 4 10 0 2 1

4 3 10 1 2 I --- (2)

(ii) loop FABCF

4 3 5 0 3 2 I I

4 3 5 3 2 I I --- (3)

From Eq. (1) and Eq. (2)

4 3 3 2 2 = 10

3 4 4 10 2 3 2

4 7 10 3 2 I I --- (4)

From Eq. (3) and Eq. (4)

10 5 2 I

I A 2 . 0 5

Negative sign indicates that I 2 current

flows from F to C

From Eq. (2) 4 3 0 5 10 1I .

I A 1 = 2 1. 2

∴ I I 3 1 I A

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