For the given quadratic equation √2 x^ 2 + 7 x+ 5 √2 = 0 (i) Find the discriminant. (ii) Comment on the nature of the roots. (iii) Find the roots.
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Step-by-step explanation:
√2x² +7x + 5√2 = 0
a= √2 , b=7 , c=5√2
WE KNOW THAT B² - 4*AC
(7)² - 4* √2 *5√2
49 - 4 * 5 * 2
49 - 40 = 9
THEREFORE THE NATURE OF THE QUADRATIC EQUATION IS REAL AND UNEQUAL
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