Question

For the given quadratic equation 5x+3y=5 state the root (A) (1 0) (B) (2 1) (C) (-1 -2) (D) (0 1)​

Answer 1

Answer:

(a) (1,0)

taking x=1& y=0

5(1)+3(0)=5

5+0

=5....

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Answer 2

Given,

The main equation is = 5x + 3y = 5

The choices of the roots are = (1,0) ; (2,1) ; (-1,-2) ; (0,1)

To find,

The correct root which will satisfy the equation.

Solution,

There is a very easy method to solve this mathematical problem. We can put the two numerical values of each root in the places of x and y, respectively. The correct root will produce the final result same as on the RHS of the given equation.

Trials :

Roots = (1,0)

Application on the LHS = (5×1) + (3×0) = 5+0 = 5

The value of LHS matches with the value of RHS.

Hence, the roots of the given equation is (1,0).