Question

for the given reaction mole of fecl2 formed on reacting 7.2 g of feo with 3.65 g hcl is??
FeO+2HCl gives fecl2 + h2o​

Answer 1

Answer:

As per the information in the equation, you need 2 moles of HCL to dissolve one mode of Iron or Fe. So you will have one mole of FeCl2 and one mole of H2(g).

As per the periodic table 1 mole of Iron weighs 55.85g

Since we have 2.8g of Fe,

It means 2.8/56.85 = 0.049 so we round it to .05 moles of Fe.

For 1 mole of Fe you need two of HCl, then for

0.05 moles of Fe you will need 0.05*2 = 0.1 moles of HCl.

One mole of HCl weighs 36.5g aprox.; then 0.1 moles will weigh 3.65g.

Answer 2

Answer:

For the given reaction mole of FeCl₂ formed is equal to 0.1 mole.

Explanation:

The given chemical reaction is ;-

FeO  +  2HCl  $\longrightarrow$   FeCl₂   +   H₂O

From the above equation we can say that the one mole of FeO react with two moles of HCl and​ formation of one mole of  FeCl₂.

Molecular mass of iron oxide FeO = 71.8 g

Molecular mass of HCl = 36.5g/mol

71.8 g of FeO reacts with mass of  HCl = 36.5g

7.2g of FeO will react with HCl $=\frac{36.5}{71.8}\times 7.2=3.65g$

Molecular mass of FeCl₂ = 126.8g/mol

So, 71.8 g of FeO will form FeCl₂ = 126.8g

Then 7.2 g of FeO will form FeCl₂ $=\frac{126.8}{71.8}\times 7.2=12.71\;g$

The number of moles of FeCl₂ will form $=\frac{12.71}{126.8}=0.1\; mole$

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