For the given reactions, A forming D; ∆H=x. Steps involved are
A forming B ; ∆ H1 = x1
B forming C ; ∆H2 = ?
C forming D ; ∆H3 = x3 .Then ∆H2 =
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7
Explanation:
here is the answer... eq 2+3-1 and reverse the eq C-> B to B->C and change the sign of the enthalpy
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Answered by
1
Answer:
x-[x1 + x3]
Explanation:
H1 + H2 + H3 = H
x1 + H2 + x3 = x
H2 = x-[x1 + x3]
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