Question

for the half cell reaction
O2+2H2O+4e-__4OH-
what will be the value of_G\FE​

Answer 1

In neutral conditions (pH 7), the reactions are

4H2O + 4e- --> 2H2 + 4OH- Eoc=0:413 V

2H2O --> O2 + 4H+ + 4e- Eoa=0:817 V

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