Question

For the hyperbola 25x2 – 16y2 = 400, find the distance between foci.

​

Answer 1

Step-by-step explanation:

25x2 + 16y2 = 1600

Given: The equation of ellipse => 25x2 + 16y2 = 1600

This equation can be expressed as By using the formula,

Eccentricity: Here, a2 = 64 and b2 = 100

Length of latus rectum = 2b2/a = [2(64)] / (100) = 32/25

Coordinates of foci (±ae, 0)

So, the ecentricity is 3/5, foci are (0, ±6) and length of the latus rectum is 32/25