Question

For the ice weighing so gram at o'c. How much heat will be required to concert it into steem at 100°℃?​

Answer 1

Answer:

We have the latent heat of fusion as 80 cal/g, specific heat of water as 1 cal/g/K and latent heat of vaporization as 540 cal/g.

Thus we get the amount of heat required as-

heat required to melt ice+heat required to raise the temperature of water from 0

o

C to 100

o

C + heat required ot vaporize water

=mL

ice

+mCΔT+mL

water

=(1×80)+(1×1×100)+(540×1)=720 cal

Answer 2

Step-by-step explanation:

Suppose

gm ice melted, then heat required for its melting =

heat avaiable with steam for being condensed and then brought to

heat lost = heat taken

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