Question

For the linear equation 3x-y =5, express ‘x’ in terms of y. Also check whether the point (1,2) lies on this line.

Answer 1

Answer:

Step-by-step explanation:

y= -5-3x ÷ -2

the point (-3, -2) lies in the line 3x-2y+5=0

Step-by-step explanation:

y in terms of x =

3x-2y+5=0

-2y= -5-3x

y= -5-3x ÷ -2

now to find whether -3,-2 lies on this line or not we need to substitute the value of x and y with -3 and -2 respectively. if the answer comes 0 then it lies on the line.

∴   3(-3) - 2(-2) + 5 = 0

-9 + 4+5 =0

-9+9=0

0=0

hence proved

the point (-3, -2) lies in the line 3x-2y+5=0

Answer 2

Answer:

3x - y = 5

3x = 5 + y      [Transposing y to RHS]

x = $\frac{5 + y}{3}$

Checking whether the point (1,2) lies on this line

Let x = 1 and y = 2

1 = $\frac{5 + 2}{3}$

1 = $\frac{7}{3}$

1 ≠ 2.33333....

Hence point (1,2) does not lies on this line