Question

For the liquid = vapour EQBM or a substrate dp /dT at 1 bar and 400k is 8x10^-3 bar/k. if the molar volume in the vapour form is 200 L/mol and the molar volume of in the liquid form is negligible, the molar enthalpy of vaporization is? ​

Answer 1

Answer:

According to Clausius - Clapeyron's equation

dTd lnP​=RT2ΔHv​​

According to this equation, the rate at which the natural logarithm of the vapor pressure of a liquid changes with temperature is determined by the molar enthalpy of vaporization of the liquid, the ideal gas constant, and the temperature of the system.

Explanation: